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p^2=0.81p
We move all terms to the left:
p^2-(0.81p)=0
We add all the numbers together, and all the variables
p^2-(+0.81p)=0
We get rid of parentheses
p^2-0.81p=0
a = 1; b = -0.81; c = 0;
Δ = b2-4ac
Δ = -0.812-4·1·0
Δ = 0.6561
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.81)-\sqrt{0.6561}}{2*1}=\frac{0.81-\sqrt{0.6561}}{2} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.81)+\sqrt{0.6561}}{2*1}=\frac{0.81+\sqrt{0.6561}}{2} $
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